Problem Statement: – Calculate the pH of the following solutions:
- 01M HCl
- 05M H2SO4
- 001M KOH
Solution:
1. pH of 0.01M HCl solution
Since HCl is a strong acid, it completely dissociates in aqueous solution
Therefore, the concentration of H+, [H+] will be 0.01M
Now, pH = – log[H+]
= – log (0.01)
= 2
2. pH of 0.05M H2SO4 solution
Since H2SO4 is a strong acid, it completely dissociates in aqueous solution
Therefore, [H+] = 0.01M
Now, pH = – log[H+]
= – log (0.1)
= 1
3. pH of 0.001M KOH solution
Since KOH is a strong base, it completely dissociates in aqueous solution
Therefore, [OH–] = 0.01M
Now, pOH = – log[OH–]
= – log (0.001)
= 3
Hence, pH = 14 – pOH = 14 – 3 = 11