The Chemistry of Art > 3. Electrons in the Atom > The Electrons in The Outer Shell >
The relationship between the number of electrons in the outer shell of an element and its electronegativity
Overview:
- If enough energy is absorbed by an atom, an electron can be completely removed, leaving behind a positively charged ion
- This amount of energy is known as ionization energy
Official Definition:
“The amount of energy needed to remove the outermost electron from one mole of gaseous atoms or ions”
Trends:
Noble gases:
- The highest ionization energies belong to the noble gases
- Indicates electron configurations are very stable
- First ionization energy decreases as you go down the noble gases group
- The outer shell is in increasingly further from the pull of the nucleus
- Increasingly shielded/repelled by inner electron shells
Group 1 alkali Metals:
- Require the least amount of ionization energy
- One electron in their valence shell is less strongly held than the electrons of the closer inner shells
- When this electron is removed, the resulting ion has a stable outer shell electron configuration
Across periods (Left to right):
- Ionisation energies (largely) increase across a period
- As successive elements have one more proton than the last
- Increased electrons are at a similar distance therefore there is a gradual increase in attractive force
Down groups
- Gradual decrease in ionization energy
- Outer electrons are further from the nucleus
- Number of electrons shielding/repelling increases
New content:
Irregularities in the above trends:
- Explained due to electron configurations and sub shells
e.g. Boron and Aluminum (Lower ionization energies than expected)
B 1s22s22p1 B+ 1s22s2
Al 1s22s22p63s23p1 Al+ 1s22s22p63s2
Boron:
- The 2p electron is removed
- The 2p subshell has a slightly higher energy than the 2s subshell
- 2p well shielded by 2s electrons
e.g. Oxygen and Sulphur (Lower ionization than expected)
O 1s22s22px22py12pz1 O+ 1s22s22px12py12pz1
S 1s22s22p63s23px23py13pz1 S+ 1s22s22p63s23px13py13pz1
Note: x,y and z denote the different orbitals in the p sub shells
Oxygen:
- The first three 2p electrons are in separate orbitals in accordance with Hund’s rule
- The additional electron must pair up with one of these
- The proximity of the two electrons in one orbital results in greater electrostatic repulsion
- Hence less energy is needed to ionize this electron from the orbital