Investigate, write equations and construct models to represent the reactions of saturated hydrocarbons when substituted with halogens

[cs_content][cs_section parallax=”false” separator_top_type=”none” separator_top_height=”50px” separator_top_angle_point=”50″ separator_bottom_type=”none” separator_bottom_height=”50px” separator_bottom_angle_point=”50″ style=”margin: 0px;padding: 45px 0px;”][cs_row inner_container=”true” marginless_columns=”false” style=”margin: 0px auto;padding: 0px;”][cs_column fade=”false” fade_animation=”in” fade_animation_offset=”45px” fade_duration=”750″ type=”1/1″ style=”padding: 0px;”][cs_text]Organic Chemistry > Products of Reactions Involving Hydrocarbons >[/cs_text][cs_text]Halogenation reaction of Alkanes

  • Experiments have shown that to trigger the reactions between halogens and alkanes, UV light is a must. Later as the reactions proceed further, presence of light is not mandatory.
  • An example of alkane halogenation is given as follows:
    1. CH4 + Cl2 = CH3Cl (chloromethane) + HCl
    2. CH3Cl + Cl2 = CH2Cl2 (dichloromethane) + HCl
    3. CH2Cl2 + Cl2 = CHCl3 (trichloromethane) + HCl
    4. CHCl3 + Cl2 = CCl4 (tetrachloromethane) + HCl

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